x^2+4x-1500=0

Solution for x^2+4x-1500=0 equation:

x^2+4x-1500=0

a = 1; b = 4; c = -1500;
Δ = b2-4ac
Δ = 42-4·1·(-1500)
Δ = 6016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6016}=\sqrt{64*94}=\sqrt{64}*\sqrt{94}=8\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{94}}{2*1}=\frac{-4-8\sqrt{94}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{94}}{2*1}=\frac{-4+8\sqrt{94}}{2}
$